AB & CD are two parallel chords drawn on two opposite sides of
their parallel diameters such that AB=6cm,CD= 8cm.if the radius of the
circle is 5cm,the distance between the chords,in cm, is
A 2 B 8
C 5 D 3
A 2 B 8
C 5 D 3
Draw a green diameter perpendicular to the red diameter, which biscects chord AB at E into two 3 cm parts, chord CD at F into two 4 cm parts, and the red diameter into two 5 cm radii
Draw in radii OA and OC, which are 5 cm each.
We use the Pythagorean theorem on right triangles OAE and OCF to find OE and OF OA² = AE² + OE² OC² = CF² + OF² 5² = 3² + OE² 5² = 4² + OF² 25 = 9 + OE² 25 = 16 + OF² 25 - 9 = OE² 25 - 16 = OF² 16 = OE² 9 = OF² 4 = OE 3 = OF
The distance between the chords = EF = OE + OF = 4 + 3 = 7cm. Therefore it is none of the choices you gave. The correct distance is 7 cm. Edwin
No comments:
Post a Comment